This is exactly what I was looking for. Line Array is awesome and was the best investment I ever made.
How do I create a java program that will take integers from a .txt file and put them into an array?
I have a set of numbers in a .txt file, 2 large groups separated by a new line, with each number separated by a space. What should I do to get these numbers into an array? Thanks.
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int x;for (x = 1; x <= NUMVALS; x++){ printf(”%d “, arr[x]); if ((x%4)==0) printf(”n”);}
Instead of saying “check that there is no repeated number (1-9) in any rows”you can make your thinking simpler by redefining the statement as “check that nos 1-9 appear exactly once in each row”now the coding becomes simpler for me at least
int box[9][9], no_to_test, count;for(int r=0);r<9;r++){ for(int c=0;c<9;c++) { no_to_test = c+1; count=0; for(int d=0;d<9;d++) { if(box[r][d]==no_to_test) { count++; } } if(count>1) { cout < <”Sudoku Violation: The digit “<< no_to_test <<” appears more than once on row no. “<< r+1<< endl <<”Any digit (1-9) can appear only once in each row of the box. Try Again!”; break; } }}I will be too much interested if you can send me the completed sudoku code because I am a big fan of it 
Although Its not an obligation but an atmosphere for a symbiotic community called yahoo! answers.Good Luck!
The homework questions crack me up. This isn’t even a question. Is this c++?! Here is a c++ answer:#includeusing namespace std;int main(void){char text[80];cout <<”Enter a string to reverse: “;cin.getline( text, 80, ‘n’);cout <<”Text reversed: “<< endl; for (int i = 0; i < strlen(text); ++i) { cout << text[strlen(text) - i - 1]; } cout << endl; return 0;}
#includeusing namespace std;int main( ){ int array[10]; int input = 0;double sum = 0.0; for (int i = 0; i < 10; i++){ cout <<"Please enter a number: "; cin >> input; array[i] = input; sum += input;}cout <<”Numbers from array: “;for (int i = 0; i < 10; i++){ cout << array[i] <<”";} cout << endl <<”Average of numbers: “<< sum / 10.0;return 0;}
Try adding trim around the output, like this:
i am not sure what ur $row is…but it seems that $row should be an array…and without knowing that it is difficult to answer ur question…if ur retriving some data from mySQL, try somethins like:first add the $row to an array..this is an example code:if(mysql_num_rows($results)>0){$row = mysql_fetch_array($results);extract($row);}
Try this’ TextBox1 – set multiline true and also set EnterKeyBehaviour = true’ Watch out – the last line may not necessarily be followed by the enter key’ The ‘vbCrLf’ is 2 chars longDim Lines As IntegerDim StringArray() As StringPrivate Sub CommandButton1_Click()Dim i As Integer, start As IntegerDim dbString As String ‘ for testing purposes Lines = 0 start = 1′ find the number of lines entered’ there MAY be a missing CR at the end, so plant one If Right(TextBox1.Text, 2) <> vbCrLf Then TextBox1.Text = TextBox1.Text & vbCrLf For i = 1 To Len(TextBox1.Text) If Mid(TextBox1.Text, i, 2) = vbCrLf Then Lines = Lines + 1 ReDim Preserve StringArray(Lines) StringArray(Lines – 1) = Mid(TextBox1.Text, start, i – start) start = i + 2 End If Next i MsgBox (”There were ” + Str(Lines) + ” lines entered.”)’ re-constitute from array, just for testing For i = 0 To Lines – 1 dbString = dbString + StringArray(i) + “.” + vbCrLf Next i MsgBox (dbString)End Sub
Here is the solution:double[] dataArray;…code related to filling 50 spots in the above array…//following code helps to display 10 elements per linefor(int counter=0; counter<50; counter++){ System.out.print(dataArray[counter]+”t”); if((counter+1)%10==0){ System.out.print(”n”); }}The above code must work.
Use Scanner and the nextInt() method to read the file.Probably something like:File f = new File(”filename.txt”);Scanner sc = new Scanner(f);int cnt = 0;while(sc.hasNext()) cnt++;Integer i[] = new Integer[cnt];cnt = 0;sc.close();sc = new Scanner(f);while(sc.hasNext()){i[cnt] = sc.nextInt();cnt++;}
A: ~ increase the separation of pulsesby shifting the array’s the point of crossover moves in degrees from point,http://www.explorelearning.com/index.cfm?method=cResource.dspExpGuide&ResourceID=590http://www.ndt.net/article/ecndt98/steel/335/335.htm..
Yes it is possible in .Net. Just replace textBox1 with the name of your textbox control.VB:Dim storedLines() as StringstoredLines= textBox1.LinestextBox1.Clear()C#:string[] storedLines = textBox1.Lines;textBox1.Clear();
By first line (by using new keyword) you just created an empty Array, not animals you have to fill that array with Animals like:a1[0][0] = new Animal();a1[0][1] = new Animal();a1[3][5] = new Animal();than u can write your code’s second line only for these instances.I can’t write a1[1][1].hunger = 0; becouse it is still “null”, (technically i can write this line but it throws a NullPointerException at runtime)This is what you did wrong but i give you an advice, using arrays are note that usefull for this situation for animals you should try using Collections like:List animalList = new ArrayList ();Animal animal0 = new Animal();animalList .add(animal0);Animal animal1 = new Animal();animalList .add(animal1);//than you can retrieve those anials from list like this:animalList.get(0).hunger = 0; //animal0animalList.get(1).hunger = 0; //animal1lists are usefull but there is a better solution Maps:If you want to use maps u need to give your animals some “unique” id or name for examplepublic class Animal {public String name;public int hunger;//other fields}than you can create map and put your animal in it like :Map animalMap = new HashMap ();Animal a1 = new Animal();Animal a2 = new Animal();a1.name = “Tom”;a2.name = “Jerry”;animalMap.put(”Tom”, a1);animalMap.put(”Jerry”, a2);//and you can retrieve your animals by calling their by name from the mapanimalMap.get(”Tom”).hunger = 0;animalMap.get(”Jerry”).hunger = 0;